{"contentHash":"53b18d480f6bc08bed35ddac210dd965668999f837357087f58a5d4bcb84f7ae","protocol":"bitcoin","authorPubkey":"fcaf320c49ec1901405bb3b88fe9d517f9617edcde18f276a3b659a1d7416c82","text":"mine solution was basically: >make a dict where the key is the allow and the value is a list of alloys known to be weaker than it >make a list of all alloys >find the alloy that isn't in any other alloy's \"weaker than\" list >that's the strongest >now iterate through the list again, ignoring the strongest alloy, to find the other alloy not in anyone's list >that's the second strongest alloy >keep iterating til you've assigned them all probably a faster way of doing it, but it's pretty simple conceptually","topicHash":"913c62c2ee31793c7e8517600dbc8f0c337afae133700a128a7d8ffb8a21c93e","topicName":"technology","parentHash":"6fb219f80ca87196401689821d04f3d95132a3ab298c893e26120fe0a8fb277b","costSunk":"0","biasSupport":0,"biasOppose":0,"biasVouch":0,"biasNull":0,"blockHeight":null,"confirmations":0,"timestamp":"2026-11-04T05:09:45.544Z","tripFp":"6c8563bf77d5","viewCount":0,"powDifficulty":0,"relation":0,"ephemeral":true,"nonce":"f0686ef1f29e8c38","sig":"d22f932284fc2b4aa31e3a03129191f2317fe519cf9936154ef98c7dc4e79a30471d23f736a24e03a8012a424ebba3703adfe5b530a7c39f37a4d884dad7be37","ephStamp":{"blockHashHex":"00000000000000000001db3692f60243aaa2b07feb7a376b6263ab3598410c92","nonceHex":"7b0b030000000000"},"replyCount":0,"chainReplyCount":0,"vaporReplyCount":0,"clusterSize":1,"receiptHeight":974484,"expiryHeight":976644,"authorMarks":{"since":"2026-11-03T19:04:47.691Z","via":"sight","inscribed":0,"likes":0,"biases":0},"lang":"en","servedBy":{"host":"6af58b1822e0cabfe57d76540f745d059b438f489a796ec6a705c6540233845e","t":"2026-11-08T20:14:56.554Z","sig":"0243fc7f2f7774ac993fa827a8c040d68bb51381288e4a41e6c458055c0bd7f6467880e74a450ca043ef149fba2acbee6571526a8d07531ffe0297f9fbaaca18","h":"00000000000000000001c6fee9ce4c94f2939fc431bac9a783a15f129c2c58b1"}}